Subject: Re: ready

From: Christopher Rose <crose>
Date: Mon, 3 Mar 97 13:44:56 EST

Hi Porlin,

I think all you need is the markov property.  You have
to find class(es) of original chains for which
certain subdivisions will be markov as well.

Yes, it can be a tough problem, but if you use
the markov principle as the guide you should be able
to identify at least one structure which always results in a 
new markov chain upon subdivision.

Good luck!

Chris Rose

PS:  And keep thepublic questions coming!